JEE Main202228 Jul 2022Evening ShiftPhysicsRay OpticsActual
The power of a lens (biconvex) is 1 . 25 m - 1 in particular medium. Refractive index of the lens is 1 . 5 and radii of curvature are 20 cm and 40 cm respectively. The refractive index of surrounding medium:
Options
- A1 . 0
- B9 7
- C3 2
- D4 3
Correct answer
D. 4 3
Step-by-step solution
Using Len's maker formula, P = 1 f = μ 1 - μ 2 1 R 1 - 1 R 2 Where, μ 1 is refractive index of lens and μ 2 is of surrounding medium. Putting the values, ⇒ 1 . 25 = 1 . 5 - μ 2 1 0 . 2 + 1 0 . 4 ⇒ 1 . 25 × 0 . 08 0 . 6 = 1 . 5 - μ 2 The refractive index of surrounding medium is μ 2 = 4 3 .