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JEE Main 202228 JulyMorning Shift
Exam
JEE Main
Year
2022
Date
28 July
Shift
Morning Shift
Subject
Physics
Chapter
Ray Optics

JEE Main 2022 · 28 July · Morning Shift · Physics · Ray Optics

As shown in the figure, after passing through the medium 1 . The...

As shown in the figure, after passing through the medium 11. The speed of light v2{v}_{2} in medium 22 will be :
(Given c=3×108ms−1c = 3 \times {10}^{8}m{s}^{- 1})

As shown in the figure, after passing through the medium 1 . The speed of light v _ 2 in medium 2 will be : (Given c =

Options

  1. A1.0×108ms−11 . 0 \times {10}^{8}m{s}^{- 1}
  2. B0.5×108ms−10 . 5 \times {10}^{8}m{s}^{- 1}
  3. C1.5×108ms−11 . 5 \times {10}^{8}m{s}^{- 1}
  4. D3.0×108ms−13 . 0 \times {10}^{8}m{s}^{- 1}

Correct answer

A. 1.0×108ms−11 . 0 \times {10}^{8}m{s}^{- 1}

Step-by-step solution

The refractive index of a medium is given by, n=μrεrn = \sqrt{{\mu}_{r}{ε}_{r}}.

For medium 22, n2=1×9=3{n}_{2} = \sqrt{1 \times 9} = 3

Now speed of light in a medium will be,

cv=n⇒v=3×1083=1×108ms−1\dfrac{c}{v} = n ⇒ v = \dfrac{3 \times {10}^{8}}{3} = 1 \times {10}^{8}m{s}^{- 1}

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