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JEE Main202227 Jul 2022Morning ShiftPhysicsRay OpticsActual

A microscope was initially placed in air (refractive index 1 ). It is then immersed in oil (refractive index 2 ). For a light whose wavelength in air is , calculate the change of microscope's resolving power due to oil and choose the correct option

Options

  1. AResolving power will be 1 4 in the oil than it was in the air
  2. BResolving power will be twice in the oil than it was in the air.
  3. CResolving power will be four times in the oil than it was in the air.
  4. DResolving power will be 1 2 in the oil than it was in the air.

Correct answer

B. Resolving power will be twice in the oil than it was in the air.

Step-by-step solution

Resolving power of microscope in air is ( R . P ) air   = 2 μ air sin θ 1 . 22 λ = 2 sin θ 1 . 22 λ ( R . P ) oil   = 2 μ oil sin θ 1 . 22 λ oil   = 2 sin θ 2 1 . 22 λ R . P oil = R . P air × 2 Thus, resolving power in oil is twice the resolving power in air.

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