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The speed of light in media ' A ' and ' B ' are 2 . 0 × 10 10 cm s - 1 and 1 . 5 × 10 10 cm s - 1 respectively. A ray of light enters from the medium B to A at an incident angle ' θ ' . If the ray suffers total internal reflection, then

Options

  1. Aθ = sin - 1 4 3
  2. Bθ > sin - 1 2 3
  3. Cθ > sin - 1 3 4
  4. Dθ < sin - 1 3 4

Correct answer

C. θ > sin - 1 3 4

Step-by-step solution

Given: v A = 2 × 10 8   m   s - 1 and v B = 1 . 5 × 10 8   m   s - 1 For critical angle: sin θ c = μ A μ B = c v A × v B c = 1 . 5 × 10 8 2 × 10 8 = 3 4 ⇒ θ c = sin - 1 3 4 Now for T I R ,   θ > θ C So, θ c > sin - 1 3 4

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