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The aperture of the objective is 24 . 4 cm . The resolving power of this telescope, if a light of wavelength 2440 A ∘ is used to see the object will be

Options

  1. A8 . 1 × 10 6
  2. B10 . 0 × 10 7
  3. C8 . 2 × 10 5
  4. D1 . 0 × 10 - 8

Correct answer

C. 8 . 2 × 10 5

Step-by-step solution

Given, The diameter of the objective lens, D = 24 . 4   cm The wavelength of the light, λ = 2440   A ∘ The resolving power of a telescope is given by, R . P = D 1 . 22 λ ⇒ R . P = 24 . 4 × 10 - 2 1 . 22 × 2440 × 10 - 10 = 8 . 2 × 10 5 Hence, the resolving power of a telescope is 8 . 2 × 10 5 .

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