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JEE Main202120 Jul 2021Morning ShiftPhysicsRay OpticsActual

Region I and II are separated by a spherical surface of radius 25 cm . An object is kept in region I at a distance of 40 cm from the surface. The distance of the image from the surface is:

Options

  1. A55 . 44   cm
  2. B9 . 52   cm
  3. C18 . 23   cm
  4. D37 . 58   cm

Correct answer

D. 37 . 58   cm

Step-by-step solution

μ 2 v - μ 1 u = μ 2 - μ 1 R 1 . 4 v - 1 . 25 - 40 = 1 . 4 - 1 . 25 - 25 1 . 4 v = - 0 . 15 25 - 1 . 25 40 v = - 37 . 58   cm Hence option ( 4 ) .

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