JEE Main20209 Jan 2020Evening ShiftPhysicsRay OpticsActual
There is a small source of light at some depth below the surface of water (refractive index = 4 3 ) in a tank of large cross sectional surface area. Neglecting any reflection from the bottom and absorption by water, percentage of light that emerges out of surface is (nearly): [Use the fact that surface area of a spherical cap of height h and radius of curvature r is 2 π r h ]
Options
- A21 %
- B34 %
- C17 %
- D50 %
Correct answer
C. 17 %
Step-by-step solution
s i n β = 3 4 , cos β = 7 4 Solid angle d Ω = 2 π R 2 1 - cos β Percentage of light = 2 π R 2 1 - cos β 4 π R 2 × 100 = 1 - c o s β 2 × 100 = 4 - 7 8 × 100 ≈ 17 %