JEE Main201912 Apr 2019Morning ShiftPhysicsRay OpticsActual
The value of numerical aperture of the objective lens of a microscope is 1.25 . If light of wavelength 5000 Å is used, the minimum separation between two points, to be seen as distinct, will be:
Options
- A0.48 μ m
- B0.24 μ m
- C0.38 μ m
- D0.12 μ m
Correct answer
B. 0.24 μ m
Step-by-step solution
R e s o l v i n g l i m i t = 0.61 λ d = 0.61 × 5000 × 10 - 10 1.25 = 0.24 μ m