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A Zener diode of breakdown voltage 10 V is used as a voltage regulator as shown in the figure. The current through the Zener diode is

Options

  1. A50 mA
  2. B0
  3. C30 mA
  4. D20 mA

Correct answer

C. 30 mA

Step-by-step solution

As Zener is in breakdown region, therefore potential drop across it would be 10 V . Now, I 3 = 10 500 = 1 50 A and I 1 = 10 200 = 1 20 A Also, I 2 = I 1 - I 3 ⇒ I 2 = 1 20 - 1 50 = 3 100 A = 30 mA

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