JEE Main202429 Jan 2024Evening ShiftPhysicsSemiconductorsActual

The truth table for this given circuit is:

Correct answer

Step-by-step solution

With respect to the above diagram, the final output can be calculated as follows: Y = A · B + A ¯ · B = ( A + A ¯ ) · B ⇒ Y = 1 . B ⇒ Y = B Hence, the required truth table can be written as follows:

Practice Semiconductors on Quantrex Academy →

More from Semiconductors

The output Y for the given inputs A and B to the circuit is: 2026 Refer to the logic circuit given below. For two inputs (A=1, B=1) and (A=0, B=1) , output (Y) will be __________. 2026 The maximum rated power of the LED is 2 mW and it is used in the circuit with input voltage of 5 V as shown in the figure below. The current through resistance R_S is 0.5 mA. The m 2026 In a semiconductor p-n diode, the doping concentrations on p-side and n-side are 10¹⁵ atoms/cm ^3 and 10¹⁸ atoms/cm ^3 , respectively. Which one of the following statements is true 2026 For the given logic circuit, which of the following inputs combination will make both LED -1 and LED -2 to glow? 2026 Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: A diode under reverse-biased condition provides very small current 2026 A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the minimum resistance to be used in series with this diode for safety when it is connected to a 25 V 2026 Two 4 bits binary numbers, A = 1101 and B = 1010 are given in the inputs of a logic circuit shown in figure below. The output (Y) will be: 2026 Full Semiconductors list All JEE Main PYQs