In the given circuit, the breakdown voltage of the Zener diode is 3 . 0 V . What is the value of I z ?

Step-by-step solution

Given that, V z = 3 V Let potential at B = 0 V Potential at E V E = 10 V Now, V C = V A = 3 V and, I z + I 1 = I . . . 1 The current through 1 kΩ resistor is given by I = 10 - 3 1000 A = 7 1000 A From the diagram, it follows that I 1 = 3 2000 A Therefore, from equation (1), it follows that I z = 7 - 1 . 5 1000 A = 5 . 5 mA