For a given transistor amplifier circuit in CE configuration V C C = 1 V , R C = 1 kΩ , R b = 100 kΩ and β = 100 . Value of base current I b is

Step-by-step solution

Considering the transistor in saturation mode, V C E = 0 Using Kirchhoff's voltage rule, - I C R C + V C C = 0 ⇒ I C = V C C R C ⇒ I C = 1   V 10 3   Ω = 10 - 3   A So, β = I C I b = 10 - 3   A I b ⇒ I b = 10 - 3 10 2 = 10 - 5   A = 10   μA