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JEE Main202224 Jun 2022Evening ShiftPhysicsSemiconductorsActual

In the given circuit, the value of current I L will be _____ mA . (When R L = 1 kΩ )

Correct answer

0

Step-by-step solution

Potential drop across the branch containing load resistance will be 5   V due to Zener diode. Therefore, potential drop across 800   Ω will be, 10   V - 5   V = 5   V . Now, current through battery will be, I = 5 800 × 1000 = 6 . 25   mA Current through load will be, I L = 5 1000   A = 5   mA

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