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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2021 · 26 August · Evening Shift · Physics · Semiconductors

Four NOR gates are connected as shown in figure. The truth table...

Four NOR gates are connected as shown in figure. The truth table for the given figure is :

Four NOR gates are connected as shown in figure. The truth table for the given figure is :

Options

  1. A{ABY001010101110\begin{cases}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{cases}
  2. B{ABY000011101110\begin{cases}A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{cases}
  3. C{ABY001010100111\begin{cases}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{cases}
  4. D{ABY000011100111\begin{cases}A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{cases}

Correct answer

C. {ABY001010100111\begin{cases}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{cases}

Step-by-step solution

Four NOR gates are connected as shown in figure. The truth table for the given figure is :

y=(A+A+B¯)¯+(B+A+B¯)¯¯y = \overset{¯}{\overset{¯}{( A + \overset{¯}{A + B} )} + \overset{¯}{( B + \overset{¯}{A + B} )}}

y=(A+A+B¯)⋅(B+A+B¯)y = ( A + \overset{¯}{A + B} ) \cdot ( B + \overset{¯}{A + B} )

{ABY001111010100\begin{cases}A & B & Y \\ 0 & 0 & 1 \\ 1 & 1 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0\end{cases}

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