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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2021 · 26 August · Evening Shift · Physics · Semiconductors

For the given circuit, the power across zener diode is _____ mW .

For the given circuit, the power across zener diode is _____ mWmW.

For the given circuit, the power across zener diode is _____ mW .

Correct answer

0

Step-by-step solution

For the given circuit, the power across zener diode is _____ mW .

i1=141×103=14mA{i}_{1} = \dfrac{14}{1 \times {10}^{3}} = 14mA

i3=105×103=2mA{i}_{3} = \dfrac{10}{5 \times {10}^{3}} = 2mA

i2=i1−i3=12mA{i}_{2} = {i}_{1} - {i}_{3} = 12mA

Power consumed in zener diode

=V×i=0.12W=120mW= V \times i = 0 . 12W = 120mW

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