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JEE Main 202124 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
24 February
Shift
Morning Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2021 · 24 February · Morning Shift · Physics · Semiconductors

If an emitter current is changed by 4mA , the collector current...

If an emitter current is changed by 4mA4mA, the collector current changes by 3.5mA3 . 5mA. The value of β\beta will be:

Options

  1. A3.53.5
  2. B0.50.5
  3. C0.8750.875
  4. D77

Correct answer

D. 77

Step-by-step solution

Iε=IC+IB{I}_{ε} = {I}_{C} + {I}_{B}

⇒ΔIε=ΔIC+ΔIB⇒ \Delta{I}_{ε} = \Delta{I}_{C} + \Delta{I}_{B}

4mA=3.5mA+ΔIB4mA = 3 . 5mA + \Delta{I}_{B}

⇒ΔIB=0.5mA⇒ \Delta{I}_{B} = 0 . 5mA

⇒β=ΔICΔIB⇒ \beta = \dfrac{\Delta{I}_{C}}{\Delta{I}_{B}}

β=3.50.5\beta = \dfrac{3 . 5}{0 . 5}

⇒β=7⇒ \beta = 7

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