Take the breakdown voltage of the zener diode used in the given circuit as 6 V . For the input voltage shown in the figure below, the time variation of the output voltage is: (Graphs drawn are schematic and not to the scale)

Step-by-step solution

A diode in forward biased acts as short circuit, since current can smoothly pass in such case. The potential difference across this is negligible. In reverse biased, initially, a negligible current can pass through it. When a voltage greater than the breakdown voltage V ∘ applied across this, the potential difference remains at the breakdown voltage. In this question, two diodes are connected in opposite polarity. At a time, one diode is in forward biased and other is reversed biased. For solution, we can ign