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JEE Main20203 Sep 2020Evening ShiftPhysicsSemiconductorsActual

If a semiconductor photo diode can detect a photon with a maximum wavelength of 400 nm , then its band gap energy is: Planck's constant h = 6 . 63 × 10 - 34 J . s Speed of light c = 3 × 10 8 m s - 1

Options

  1. A1 . 1   eV
  2. B2 . 0   eV
  3. C1 . 5   eV
  4. D3 . 1   eV

Correct answer

D. 3 . 1   eV

Step-by-step solution

λ = 400   nm Band gap E 0 = hc λ = 1237 . 5 400 = 3 . 09   eV

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