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JEE Main 20203 SeptemberEvening Shift

Exam: JEE Main
Year: 2020
Date: 3 September
Shift: Evening Shift
Subject: Physics
Chapter: Semiconductors

JEE Main 2020 · 3 September · Evening Shift · Physics · Semiconductors

If a semiconductor photo diode can detect a photon with a maximum...

If a semiconductor photo diode can detect a photon with a maximum wavelength of

400nm

, then its band gap energy is: Planck's constant

h = 6 . 63 \times {10}^{- 34}J . s

Speed of light

c = 3 \times {10}^{8}m{s}^{- 1}

Options

A $1 . 1eV$
B $2 . 0eV$
C $1 . 5eV$
D $3 . 1eV$

Correct answer

D. $3 . 1eV$

Step-by-step solution

$\lambda = 400nm$

Band gap ${E}_{0} = \dfrac{hc}{\lambda} = \dfrac{1237 . 5}{400} = 3 . 09eV$

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