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JEE Main 20209 JanuaryEvening Shift

Exam: JEE Main
Year: 2020
Date: 9 January
Shift: Evening Shift
Subject: Physics
Chapter: Semiconductors

JEE Main 2020 · 9 January · Evening Shift · Physics · Semiconductors

The current i in the network is

The current

i

in the network is

The current i in the network is

The current i in the network is

Options

A $0.2A$
B $0.6A$
C $0.3A$
D $0A$

Correct answer

C. $0.3A$

Step-by-step solution

Both the diodes are in reverse biased.
The current i in the network is

The current i in the network is

I = \dfrac{9}{30} = \dfrac{3}{10}A = 0.3A

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