Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 20209 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
9 January
Shift
Evening Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2020 · 9 January · Evening Shift · Physics · Semiconductors

In the circuit shown below, is working as a 8Vdc regulated voltage...

In the circuit shown below, is working as a 8Vdc8Vdc regulated voltage source. When 12V12V is used as an input, the power dissipated (in mWmW ) in each diode is (Considering both zener diodes are identical)

In the circuit shown below, is working as a 8Vdc regulated voltage source. When 12V is used as an input, the power

Correct answer

40

Step-by-step solution

i=(12−8)(200+200)A=4400=10−2Ai = \dfrac{\left(12 - 8\right)}{\left(200 + 200\right)}A = \dfrac{4}{400} = {10}^{- 2}A
Power loss in each diode=(4)(10−2)W=40mW= \left(4\right)\left({10}^{- 2}\right)W = 40mW
Practice Semiconductors on Quantrex Academy →

More from Semiconductors

The output Y for the given inputs A and B to the circuit is: JEE Main 2026Refer to the logic circuit given below. For two inputs (A=1, B=1) and (A=0, B=1) , output… JEE Main 2026The maximum rated power of the LED is 2 mW and it is used in the circuit with input… JEE Main 2026In a semiconductor p-n diode, the doping concentrations on p-side and n-side are 10^ 15… JEE Main 2026For the given logic circuit, which of the following inputs combination will make both LED… JEE Main 2026Given below are two statements: one is labelled as Assertion A and the other is labelled… JEE Main 2026A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the… JEE Main 2026Two 4 bits binary numbers, A = 1101 and B = 1010 are given in the inputs of a logic… JEE Main 2026 Full Semiconductors list All JEE Main PYQs