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JEE Main 201912 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
12 April
Shift
Evening Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2019 · 12 April · Evening Shift · Physics · Semiconductors

Figure shows a DC voltage regulator circuit, with a Zener diode of...

Figure shows a DCDC voltage regulator circuit, with a Zener diode of breakdown voltage =6V= 6V . If the unregulated input voltage varies between 10V10V to 16V,16V, then what is the maximum Zener current?
Figure shows a DC voltage regulator circuit, with a Zener diode of breakdown voltage = 6V . If the unregulated input

Options

  1. A1.5mA1.5mA
  2. B3.5mA3.5\text{mA}
  3. C7.5mA7.5mA
  4. D2.5mA2.5mA

Correct answer

B. 3.5mA3.5\text{mA}

Step-by-step solution

Figure shows a DC voltage regulator circuit, with a Zener diode of breakdown voltage = 6V . If the unregulated input
Current through 2KΩ2KΩ is
i=102000=5mAi = \dfrac{10}{2000} = 5mA
Current through 4 KΩKΩ
iL=i−iz=64000=1.5mA{i}_{L} = i - {i}_{z} = \dfrac{6}{4000} = 1.5mA
⇒iz=i−1.5⇒ {i}_{z} = i - 1.5

∴iz=5−1.5=3.5mA∴ {i}_{z} = 5 - 1 .5 = 3 .5 mA

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