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JEE Main201912 Apr 2019Morning ShiftPhysicsSemiconductorsActual

The truth table for the circuit given in the figure is:

Options

  1. AA B Y 0 0 0 0 1 0 1 0 1 1 1 1
  2. BA B Y 0 0 1 0 1 0 1 0 0 1 1 0
  3. CA B Y 0 0 1 0 1 1 1 0 1 1 1 1
  4. DA B Y 0 0 1 0 1 1 1 0 0 1 1 0

Correct answer

D. A B Y 0 0 1 0 1 1 1 0 0 1 1 0

Step-by-step solution

C = A + B and y = A . C ¯ A B C = ( A + B ) A C y = A . C ¯ 0 0 0 0 1 0 1 1 0 1 1 0 1 1 0 1 1 1 1 0

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