The truth table for the circuit given in the figure is:

Options

A $\left|$ $\begin{array}{ll}A B Y\end{array}$ \begin{cases}0 & 0 & 0\end{cases}\begin{cases}0 & 1 & 0\end{cases}\begin{cases}1 & 0 & 1\end{cases}\begin{cases}1 & 1 & 1\end{cases} $\right|$
B $\left|$ $\begin{array}{ll}A B Y\end{array}$ \begin{cases}0 & 0 & 1\end{cases}\begin{cases}0 & 1 & 0\end{cases}\begin{cases}1 & 0 & 0\end{cases}\begin{cases}1 & 1 & 0\end{cases} $\right|$
C $\left|$ \begin{cases}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{cases} $\right|$
D $\left|$ \begin{cases}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0\end{cases} $\right|$

Correct answer

D. $\left|$ \begin{cases}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0\end{cases} $\right|$

Step-by-step solution

The truth table for the circuit given in the figure is:

$C = A + B$
and $y = \overset{¯}{A . C}$

$\begin{cases}A & B & C = ( A + B ) & AC & y = \overset{¯}{A . C} \\ 0 & 0 & 0 & 0 & 1 \\ 0 & 1 & 1 & 0 & 1 \\ 1 & 0 & 1 & 1 & 0 \\ 1 & 1 & 1 & 1 & 0\end{cases}$

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