A common emitter amplifier circuit, built using an NPN transistor, is shown in the figure. Its dc current gain is $250$ , ${R}_{C} = 1kΩ$ and ${V}_{CC} = 10V$ . The minimum base current for ${V}_{CE}$ to reach saturation is

Question

A common emitter amplifier circuit, built using an NPN transistor, is shown in the figure. Its dc current gain is

250

,

{R}_{C} = 1kΩ

and

{V}_{CC} = 10V

. The minimum base current for

{V}_{CE}

to reach saturation is

A common emitter amplifier circuit, built using an NPN transistor, is shown in the figure. Its dc current gain is 250 ,

Quantrex Academy · Accepted Answer

Correct answer: B. 40

Given, β = 250 R _ C = 1000Ω V _ CC = 10V At saturation, V _ CE = 0 ⇒ i _ e = (10V)/(1000Ω) = 10mA Current gain factor, β = i _ e i _ B ⇒ i _ B = i _ e β = (10mA)/(250) = 40

A common emitter amplifier circuit, built using an NPN transistor,...

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