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JEE Main20198 Apr 2019Evening ShiftPhysicsSemiconductorsActual

A common emitter amplifier circuit, built using an NPN transistor, is shown in the figure. Its dc current gain is 250 , R C = 1 kΩ and V C C = 10 V . The minimum base current for V C E to reach saturation is

Options

  1. A10 μ A
  2. B40 μ A
  3. C7 μ A
  4. D100 μ A

Correct answer

B. 40 μ A

Step-by-step solution

Given, β = 250 R C = 1000   Ω V C C = 10   V At saturation, V C E = 0 ⇒ i e = 10   V 1000   Ω = 10   m A Current gain factor, β = i e i B ⇒ i B = i e β = 10   m A 250 = 40   μ A

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