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JEE Main20198 Apr 2019Morning ShiftPhysicsSemiconductorsActual

The reverse break down voltage of a Zener diode is 5.6 V in the given circuit. The current I z through the Zener is:

Options

  1. A10 m A
  2. B7 m A
  3. C17 m A
  4. D15 m A

Correct answer

A. 10 m A

Step-by-step solution

i 1 - i z = V z 800 = 5.6 800 = 7   m A For loop ABCF, 9 - 200   i 1 - V z = 0 i 1 = 0.017   o r   17   m A i z = i 1 - 7   m A = 10   m A

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