Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 201816 AprilOnline
Exam
JEE Main
Year
2018
Date
16 April
Mode
Online
Subject
Physics
Chapter
Semiconductors

JEE Main 2018 · 16 April · Online · Physics · Semiconductors

In the given circuit the current through zener diode is:

In the given circuit the current through zener diode is:
In the given circuit the current through zener diode is:

Options

  1. A3.3mA3 . 3mA
  2. B2.5mA2 . 5mA
  3. C5.5mA5 . 5mA
  4. D6.7mA6 . 7mA

Correct answer

A. 3.3mA3 . 3mA

Step-by-step solution

VAB=10V∴VBC=5V{V}_{AB} = 10V∴ {V}_{BC} = 5V, the current in R1=I1=5500{R}_{1} = {I}_{1} = \dfrac{5}{500}
⇒I1=10mA⇒ {I}_{1} = 10mA. Current in R2=I2=101500⇒I2=203mA{R}_{2} = {I}_{2} = \dfrac{10}{1500}⇒ {I}_{2} = \dfrac{20}{3}mA

Current in zener diode = I1−I2=(10−203)mA=103mA{I}_{1} - {I}_{2} = \left(10 - \dfrac{20}{3}\right)mA = \dfrac{10}{3}mA

In the given circuit the current through zener diode is:
Practice Semiconductors on Quantrex Academy →

More from Semiconductors

The output Y for the given inputs A and B to the circuit is: JEE Main 2026Refer to the logic circuit given below. For two inputs (A=1, B=1) and (A=0, B=1) , output… JEE Main 2026The maximum rated power of the LED is 2 mW and it is used in the circuit with input… JEE Main 2026In a semiconductor p-n diode, the doping concentrations on p-side and n-side are 10^ 15… JEE Main 2026For the given logic circuit, which of the following inputs combination will make both LED… JEE Main 2026Given below are two statements: one is labelled as Assertion A and the other is labelled… JEE Main 2026A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the… JEE Main 2026Two 4 bits binary numbers, A = 1101 and B = 1010 are given in the inputs of a logic… JEE Main 2026 Full Semiconductors list All JEE Main PYQs