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JEE Main 20257 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Evening Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2025 · 7 April · Evening Shift · Physics · Units and Dimensions

Match List-I with List-II. List-I List-II (A) Mass density (I) [...

Match List-I with List-II.
List-IList-II
(A)Mass density(I){\left[ML^2 T^{-3}\right]}
(B)Impulse(II){\left[MLT^{-1}\right]}</td></tr><tr><td>(C)</td><td>Power</td><td>(III)</td><td>{\left[ML^2 T⁰\right]}
(D)Momentofinertia</td><td>(IV)</td><td>[ ML −3T0]of inertia</td><td>(IV)</td><td>{\left[\text{ ML }^{-3} T⁰\right]}

Choose the correct answer from the options given below :

Options

  1. A(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  2. B(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
  3. C(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  4. D(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Correct answer

C. (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

Step-by-step solution

(A) Mass density =MV=M1L−3=\frac{M}{V}=M^1 L^{-3}...(iv)
(B) Impulse =M×=\mathrm{M} \times\mathrm{u}=\mathrm{M}1 L1 T−1^1 \mathrm{~L}^1 \mathrm{~T}^{-1}....(ii)
(C) Power =F.=\mathrm{F}.\mathrm{V}=\mathrm{M}1 L2 T−3^1 \mathrm{~L}^2 \mathrm{~T}^{-3}....(i)
(D) Moment of inertia =Mr2=M1 L2=\mathrm{Mr}^2=\mathrm{M}^1 \mathrm{~L}^2...(iii)
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