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JEE Main 20257 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Morning Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2025 · 7 April · Morning Shift · Physics · Units and Dimensions

If _0 denotes the permittivity of free space and _ E is the flux of...

If ϵ0\epsilon_0 denotes the permittivity of free space and ΦE\Phi_{\mathrm{E}} is the flux of the electric field through the area bounded by the closed surface, then dimension of (ϵ0 dϕEdt)\left(\epsilon_0 \frac{\mathrm{~d} \phi_{\mathrm{E}}}{\mathrm{dt}}\right) are that of :

Options

  1. AElectric field
  2. BElectric potential
  3. CElectric charge
  4. DElectric current

Correct answer

D. Electric current

Step-by-step solution

We know that formula for displacement current is given by
id=ε0 dϕεdt\mathrm{id}=\varepsilon_0 \frac{\mathrm{~d} \phi_{\varepsilon}}{\mathrm{dt}}
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