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JEE Main 202523 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
23 January
Shift
Evening Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2025 · 23 January · Evening Shift · Physics · Units and Dimensions

Match List - I with List - II. array llll & - I & & - II (A) &...

Match List - I with List - II. \textList−I\textList−II (A)  Permeability of free space  (I) [ML2T−2] (B)  Magnetic field  (II) [MT−2A−1] (C)  Magnetic moment  (III) [MLT−2A−2] (D)  Torsional constant  (IV) [L2A]\begin{array}{llll} & \textList - I & & \textList - II \\ \text{ (A) } & \text{ Permeability of free space } & \text{ (I) }\left[\mathrm{M} \mathrm{ L}^2 \mathrm{ T}^{-2}\right] \\ \text{ (B) } & \text{ Magnetic field } & \text{ (II) }\left[\mathrm{M} \mathrm{ T}^{-2} \mathrm{ A}^{-1}\right] \\ \text{ (C) } & \text{ Magnetic moment } & \text{ (III) }\left[\mathrm{M} \mathrm{ L} \mathrm{ T}^{-2} \mathrm{ A}^{-2}\right] \\ \text{ (D) } & \text{ Torsional constant } & \text{ (IV) }\left[\mathrm{L}^2 \mathrm{ A}\right] \end{array} Choose the correct answer from the options given below :

Options

  1. A(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  2. B(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  3. C(A)-(I), (B)-(IV), (C)-(II), (D)-(III)
  4. D(A)-(II), (B)-(I), (C)-(III), (D)-(IV)

Correct answer

B. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Step-by-step solution

(A) B=μ0i2πr&qvB=FB=\frac{\mu_0 i}{2 \pi r} \& q v B=F μ0≡Bri≡Frqvi≡MLT−2×L A2TLT−1≡MLT−2A−2\mu_0 \equiv \frac{B r}{i} \equiv \frac{F r}{q v i} \equiv \frac{\mathrm{MLT}^{-2} \times L}{\mathrm{~A}^2 \mathrm{TLT}^{-1}} \equiv \mathrm{MLT}^{-2} A^{-2} (B) B≡FqV≡MLT−2ATLT−1=MT−2 A−1B \equiv \frac{F}{q V} \equiv \frac{\mathrm{MLT}^{-2}}{\mathrm{ATLT}^{-1}}=\mathrm{MT}^{-2} \mathrm{~A}^{-1} (C) M=iA≡AL2M=i A \equiv \mathrm{AL}^2 (D) τ=Cθ⇒C≡ML2 T−2\tau=C \theta \Rightarrow C \equiv \mathrm{ML}^2 \mathrm{~T}^{-2}
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