JEE Main202523 Jan 2025Morning ShiftPhysicsUnits and DimensionsActual
The position of a particle moving on x -axis is given by x(t)=A t+B ^2 t+C t^2+D , where t is time. The dimension of A B C D is
Options
- AL^2 T⁻²
- BL^2
- CL
- DL^3 ~T ⁻²
Correct answer
A. L^2 T⁻²
Step-by-step solution
aligned & Dimension [ x ( t )]=[ L ] & [ A ]=[ L ] & [ B ]=[ L ] & [ C ]= [ LT ⁻² ] & [ D ]=[ L ] & [ ABC D ]= [ L L LT ⁻² ~L ]= [ L ^2 ~T ⁻² ] aligned