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JEE Main 20238 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
8 April
Shift
Morning Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2023 · 8 April · Morning Shift · Physics · Units and Dimensions

Dimension of 1 μ _ 0 ε _ 0 should be equal to

Dimension of 1μ0ε0\dfrac{1}{{\mu}_{0}{ε}_{0}} should be equal to

Options

  1. ALT−1L{T}^{- 1}
  2. BT2L−2{T}^{2}{L}^{- 2}
  3. CL2T−2{L}^{2}{T}^{- 2}
  4. DTL−1T{L}^{- 1}

Correct answer

C. L2T−2{L}^{2}{T}^{- 2}

Step-by-step solution

The speed of light can be written as

c=1μ0ε0...(1)c = \dfrac{1}{\sqrt{{\mu}_{0}{ε}_{0}}} . . . \left(1\right)

Rearrange equation (1) to obtain the required quantity.

1μ0ε0=c2...(2)\dfrac{1}{{\mu}_{0}{ε}_{0}} = {c}^{2} . . . \left(2\right)

Use the method of dimensional analysis to obtain the dimension of the required quantity.

{[1μ0ε0]=[LT−1]2=L2T−2\begin{cases}\left[\dfrac{1}{{\mu}_{0}{ε}_{0}}\right] & = & {\left[L{T}^{- 1}\right]}^{2} \\ & = & {L}^{2}{T}^{- 2}\end{cases}

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