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JEE Main 20231 FebruaryMorning Shift
Exam
JEE Main
Year
2023
Date
1 February
Shift
Morning Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2023 · 1 February · Morning Shift · Physics · Units and Dimensions

(P + a V ^ 2 )(V - b) = RT represents the equation of state of some...

(P+aV2)(V−b)=RT\left(P + \dfrac{a}{{V}^{2}}\right)\left(V - b\right) = RT represents the equation of state of some gases. Where PP is the pressure, VV is the volume, TT is the temperature and a,b,Ra, b, R are the constants. The physical quantity, which has dimensional formula as that of b2a\dfrac{{b}^{2}}{a} , will be :

Options

  1. ABulk modulus
  2. BModulus of rigidity
  3. CCompressibility
  4. DEnergy density

Correct answer

C. Compressibility

Step-by-step solution

According to the principle of dimensional homogeneity, the dimensions of each terms of a dimensional equation on both sides are the same.

So, dimension of bb and VV will be same, \left[b\right] = [V]\left[V\right]

And dimension of aV2\dfrac{a}{{V}^{2}} and PP will be same, \left[\dfrac{a}{{V}^{2}}\right] = \left[P\right]</p><p>Fromabovetworelations,wehave[ab2]=</p><p>From above two relations, we have \left[\dfrac{a}{{b}^{2}}\right] =\left[P\right]</p><p></p><p>∴ \left[\dfrac{{b}^{2}}{a}\right] = \dfrac{1}{\left[P\right]} = {\left[M{L}^{- 1}{T}^{- 2}\right]}^{- 1}</p><p>Thus,[M−1L1T2]</p><p>Thus, \left[{M}^{- 1}{L}^{1}{T}^{2}\right] is the dimension of compressibility.

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