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JEE Main 20208 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
8 January
Shift
Morning Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2020 · 8 January · Morning Shift · Physics · Units and Dimensions

The dimension of stopping potential V _ 0 in photoelectric effect...

The dimension of stopping potential V0{V}_{0} in photoelectric effect in units of Planck’s constant ‘ hh ’, speed of light ‘ cc ’ and Gravitational constant ‘ GG ’ and ampere AA is:

Options

  1. Ah13G23c13A−1{h}^{\dfrac{1}{3}}{G}^{\dfrac{2}{3}}{c}^{\dfrac{1}{3}}{A}^{- 1}
  2. Bh0c5G−1A−1{h}^{0}{c}^{5}{G}^{- 1}{A}^{- 1}
  3. Ch−23c−13G43A−1{h}^{- \dfrac{2}{3}}{c}^{- \dfrac{1}{3}}{G}^{\dfrac{4}{3}}{A}^{- 1}
  4. Dh2G32c13A−1{h}^{2}{G}^{\dfrac{3}{2}}{c}^{\dfrac{1}{3}}{A}^{- 1}

Correct answer

B. h0c5G−1A−1{h}^{0}{c}^{5}{G}^{- 1}{A}^{- 1}

Step-by-step solution

V=K(h)a(I)b(G)c(C)dV = K{( h )}^{a}{( I )}^{b}{( G )}^{c}{( C )}^{d} (V is voltage)
We know [h]=ML2T−1[ h ] = M{L}^{2}{T}^{- 1}
[I]=A[ I ] = A
[G]=M−1L3T−2[ G ] = {M}^{- 1}{L}^{3}{T}^{- 2}
[C]=LT−1[ C ] = L{T}^{- 1}
[V]=ML2T−3A−1[ V ] = M{L}^{2}{T}^{- 3}{A}^{- 1}
ML2T−3A−1=(ML2T−1)a(A)b(M−1L3T−2)c(LT−1)dM{L}^{2}{T}^{- 3}{A}^{- 1} = {( M{L}^{2}{T}^{- 1} )}^{a}{( A )}^{b}{( {M}^{- 1}{L}^{3}{T}^{- 2} )}^{c}{( L{T}^{- 1} )}^{d}
ML2T−3A−1=Ma−cL2a+3c+dT−a−2c−dAbM{L}^{2}{T}^{- 3}{A}^{- 1} = {M}^{a - c}{L}^{2a + 3c + d}{T}^{- a - 2c - d}{A}^{b}
a−c=1.....(1)a - c = 1 . . . . . ( 1 )
2a+3c+d=2.....(2)2a + 3c + d = 2 . . . . . ( 2 )
−a−2c−d=−3.....(3)- a - 2c - d = - 3 . . . . . ( 3 )
b=−1...(4)b = - 1 . . . ( 4 )
On solving
c=−1c = - 1
a=0a = 0
d=5,b=−1d = 5, b = - 1
V=K(h)0(A)−1(G)−1(C)5V = K{( h )}^{0}{( A )}^{- 1}{( G )}^{- 1}{( C )}^{5}
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