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JEE Main 20207 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Evening Shift
Subject
Physics
Chapter
Units and Dimensions

JEE Main 2020 · 7 January · Evening Shift · Physics · Units and Dimensions

Given, B is magnetic field induction, and μ _ 0 is the magnetic...

Given, BB is magnetic field induction, and μ0{\mu}_{0} is the magnetic permeability of vacuum. The dimension of B22μ0\dfrac{{B}^{2}}{2{\mu}_{0}} is:

Options

  1. AMLT−2{MLT}^{- 2}
  2. BML2T−1{ML}^{2}{T}^{- 1}
  3. CML2T−2{ML}^{2}{T}^{- 2}
  4. DML−1T−2{ML}^{- 1}{T}^{- 2}

Correct answer

D. ML−1T−2{ML}^{- 1}{T}^{- 2}

Step-by-step solution

Energy density in magnetic filed =energyvolume=B22μ0= \dfrac{energy}{volume} = \dfrac{{B}^{2}}{2{\mu}_{0}}
=Force×displacement(displacement)3=MLT−2.LL3=ML−1T−2= \dfrac{Force \times displacement}{{\left(displacement\right)}^{3}} = \dfrac{ML{T}^{- 2} . L}{{L}^{3}} = {ML}^{- 1}{T}^{- 2}
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