JEE Main20264 April 2026Morning ShiftPhysicsWave OpticsActual
An unpolarized light is incident on the plane interface of air-dielectric medium shown in figure. If the incident angle is equal to Brewster angle, identify the expression representing reflected wave.
Options
- A(E_x i + E_y j ) (kx - kz - t)
- B(E_x i + E_z k ) (kx + ky - t)
- C(E_x j + E_y k ) (ky + kz - t)
- D(E_x i + E_y j + E_z k ) (kx + ky - kz - t)
Correct answer
A. (E_x i + E_y j ) (kx - kz - t)
Step-by-step solution
From the given figure, the incident light rays lie in the xz -plane. Therefore, the plane of incidence is the xz -plane. The incident wave travels from the air ( z 0 ), so it propagates in the +x and +z directions. The reflected wave will travel back into the air, meaning it propagates in the +x and -z directions. The wave vector for the reflected wave can be written as k _r = k_x i - k_z k . The phase of the reflected wave is given by k _r r - t = k_x x - k_z z - t . This phase matches the expression in option (1)