In single slit diffraction pattern, the wavelength of light used is 628 nm and slit width is 0.2 mm, the angular width of central maximum is 10⁻² degrees. The value of is _______.

Step-by-step solution

The angular width of the central maximum in a single slit diffraction pattern is given by = 2 a Substituting the given values: = 628 10⁻⁹ m a = 0.2 10⁻³ m = 2 628 10⁻⁹ 0.2 10⁻³ rad = 6280 10⁻⁶ rad = 6.28 10⁻³ rad To convert radians to degrees, multiply by 180 : = 6.28 10⁻³ 180 3.14 degrees = 2 10⁻³ 180 degrees = 360 10⁻³ degrees = 36 10⁻² degrees Comparing this with 10⁻² degrees, we get = 36 . Answer: 36