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JEE Main 202623 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
23 January
Shift
Morning Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2026 · 23 January · Morning Shift · Physics · Wave Optics

In two separate Young's double-slit experimental set-ups and two...

In two separate Young's double-slit experimental set-ups and two monochromatic light sources of different wavelengths are used to get fringes of equal width. The ratios of the slits separations and that of the wavelengths of light used are 2:12: 1 and 1:21: 2 respectively. The corresponding ratio of the distances between the slits and the respective screens (D1/D2D_{1} / D_{2}) is ____\_\_\_\_.

Correct answer

4

Step-by-step solution

Fringe width in double slit: β=λDd\beta = \frac{\lambda D}{d}
Given: d1d2=2:1\frac{d_1}{d_2} = 2:1 and λ1λ2=1:2\frac{\lambda_1}{\lambda_2} = 1:2, with equal fringe widths
For equal fringe widths: λ1D1d1=λ2D2d2\frac{\lambda_1 D_1}{d_1} = \frac{\lambda_2 D_2}{d_2}
λ1λ2×D1D2=d1d2\frac{\lambda_1}{\lambda_2} \times \frac{D_1}{D_2} = \frac{d_1}{d_2}
12×D1D2=2\frac{1}{2} \times \frac{D_1}{D_2} = 2
D1D2=4\frac{D_1}{D_2} = 4
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