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JEE Main 202524 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
24 January
Shift
Evening Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2025 · 24 January · Evening Shift · Physics · Wave Optics

In a Young's double slit experiment, three polarizers are kept as...

In a Young's double slit experiment, three polarizers are kept as shown in the figure. The transmission axes of P1P_1 and P2P_2 are orthogonal to each other. The polarizer P3P_3 covers both the slits with its transmission axis at 45∘45^{\circ} to those of P1P_1 and P2P_2. An unpolarized light of wavelength λ\lambda and intensity I0I_0 is incident on P1P_1 and P2P_2. The intensity at a point after P3P_3 where the path difference between the light waves from s1s_1 and s2s_2 is λ3\frac{\lambda}{3}, is In a Young's double slit experiment, three polarizers are kept as shown in the figure. The transmission axes of P_1 and

Options

  1. AI02\frac{I_0}{2}
  2. BI04\frac{I_0}{4}
  3. C\frac{\mathrm{I}_0}{3}
  4. DI0I_0

Correct answer

B. I04\frac{I_0}{4}

Step-by-step solution

In a Young's double slit experiment, three polarizers are kept as shown in the figure. The transmission axes of P_1 and
after passing through third poleriser, Intensity of both the waves must be \frac{\mathrm{I}_0}{4} now, at a point where path diff is λ3\frac{\lambda}{3}, phase difference Δϕ=2 K(Δxλ)=2π3∴Ires=(I04)2+(I04)2+2(I04)2cos⁡2π3=I04\begin{aligned} & \Delta \phi=2 \mathrm{~K}\left(\frac{\Delta \mathrm{x}}{\lambda}\right)=\frac{2 \pi}{3} \\ & \therefore \mathrm{I}_{\mathrm{res}}=\sqrt{\left(\frac{\mathrm{I}_0}{4}\right)^2+\left(\frac{\mathrm{I}_0}{4}\right)^2+2\left(\frac{\mathrm{I}_0}{4}\right)^2} \cos \frac{2 \pi}{3} \\ & =\frac{\mathrm{I}_0}{4} \end{aligned}
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