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JEE Main202523 Jan 2025Evening ShiftPhysicsWave OpticsActual

The width of one of the two slits in Young's double slit experiment is d while that of the other slit is x ~d . If the ratio of the maximum to the minimum intensity in the interference pattern on the screen is 9: 4 then what is the value of x ? (Assume that the field strength varies according to the slit width.)

Options

  1. A4
  2. B5
  3. C3
  4. D2

Correct answer

B. 5

Step-by-step solution

aligned & I ( width )^2 & ( I ₁ + I ₂ I ₁ - I ₂ )^2= 9 4 & I ₁ + I ₂ I ₁ - I ₂ = 3 2 & ( x +1) d ( x -1) d = 3 2 & 3 x -3=2 x +2 & x =5 aligned

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