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JEE Main 202522 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Morning Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2025 · 22 January · Morning Shift · Physics · Wave Optics

Given below are two statements : one is labelled as Assertion (A)...

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion-(A) : If Young's double slit experiment is performed in an optically denser medium than air, then the consecutive fringes come closer. Reason-(R) : The speed of light reduces in an optically denser medium than air while its frequency does not change. In the light of the above statements, choose the most appropriate answer from the options given below :

Options

  1. ABoth (A)(\mathbf{A}) and (R)(\mathbf{R}) are true but (R)(\mathbf{R}) is not the correct explanation of (A)(\mathbf{A})
  2. BBoth (A)(\mathbf{A}) and (R)(\mathbf{R}) are true and (R)(\mathbf{R}) is the correct explanation of (A)(\mathbf{A})
  3. C(A) is true but (R) is false
  4. D(A)(A) is false but (R) is true

Correct answer

B. Both (A)(\mathbf{A}) and (R)(\mathbf{R}) are true and (R)(\mathbf{R}) is the correct explanation of (A)(\mathbf{A})

Step-by-step solution

β( fringe width )=λDd\beta(\text{ fringe width })=\frac{\lambda D}{d} In denser medium, λ↓⇒β↓⇒\lambda \downarrow \Rightarrow \beta \downarrow \Rightarrow fringe come closer Also, μ=cV⇒V=cμ\mu=\frac{\mathrm{c}}{\mathrm{V}} \Rightarrow \mathrm{V}=\frac{\mathrm{c}}{\mu} Frequency remains same, ⇒μ=λvac.fλmedf⇒λmed=λvac.μ\Rightarrow \mu=\frac{\lambda_{\mathrm{vac} .} \mathrm{f}}{\lambda_{\mathrm{med}} \mathrm{f}} \Rightarrow \lambda_{\mathrm{med}}=\frac{\lambda_{\mathrm{vac} .}}{\mu}
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