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JEE Main 20246 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
6 April
Shift
Evening Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2024 · 6 April · Evening Shift · Physics · Wave Optics

Two coherent monochromatic light beams of intensities I and 4 I are...

Two coherent monochromatic light beams of intensities I and 4I4 \mathrm{I} are superimposed. The difference between maximum and minimum possible intensities in the resulting beam is xIx \mathrm{I}. The value of xx is _________.

Correct answer

0

Step-by-step solution

Imax⁡=(I+4I)2=9IImin⁡=(4I−I)2=I∴Imax⁡−Imin⁡=8I\begin{aligned} & I_{\max }=(\sqrt{\mathrm{I}}+\sqrt{4 \mathrm{I}})^2=9 \mathrm{I} \\ & \mathrm{I}_{\min }=(\sqrt{4 \mathrm{I}}-\sqrt{\mathrm{I}})^2=\mathrm{I} \\ & \therefore \mathrm{I}_{\max }-\mathrm{I}_{\min }=8 \mathrm{I}\end{aligned}
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