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The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum of the minimum intensity in the interference pattern is:

Options

  1. A1: 1
  2. B4: 1
  3. C9: 1
  4. D16: 1

Correct answer

C. 9: 1

Step-by-step solution

Since, Intensity width of slit ( ) aligned & so, I₁=I, I₂=4 I & I_ = ( I₁ - I₂ )^2=I & I_ = ( I₁ + I₂ )^2=9 I & I_ I_ = 9 I I = 9 1 aligned

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