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JEE Main 202331 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Morning Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2023 · 31 January · Morning Shift · Physics · Wave Optics

Two polaroids AandB are placed in such a way that the pass-axis of...

Two polaroids AandBA\text{and}B are placed in such a way that the pass-axis of polaroids are perpendicular to each other. Now, another polaroid CC is placed between AandBA\text{and}B bisecting angle between them. If intensity of unpolarised light is I0{I}_{0} then intensity of transmitted light after passing through polaroid BB will be :Two polaroids AandB are placed in such a way that the pass-axis of polaroids are perpendicular to each other. Now,

Options

  1. AI04\dfrac{{I}_{0}}{4}
  2. BI02\dfrac{{I}_{0}}{2}
  3. CI08\dfrac{{I}_{0}}{8}
  4. DZero

Correct answer

C. I08\dfrac{{I}_{0}}{8}

Step-by-step solution

Two polaroids AandB are placed in such a way that the pass-axis of polaroids are perpendicular to each other. Now,

As given here, the pass axis of polaroids AA and BB are inclined at angle of 90º90 º with each other. Another polaroid CCis placed at angle of 45°45 °with respect to AA and BB.

Therefore, intensity of light after falling on polaroid A,IA=I02A, {I}_{A} = \dfrac{{I}_{0}}{2}

Intensity of light after falling on polaroid C,IC=IAcos⁡245°=I02cos⁡245°=I04C, {I}_{C} = {I}_{A}\cos^{2}45 ° = \dfrac{{I}_{0}}{2}\cos^{2}45 ° = \dfrac{{I}_{0}}{4}

Intensity of light after falling on polaroid B,IB=ICcos⁡245°=I04cos⁡245°=I08B, {I}_{B} = {I}_{C}\cos^{2}45 ° = \dfrac{{I}_{0}}{4}\cos^{2}45 ° = \dfrac{{I}_{0}}{8}

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