JEE Main202229 Jun 2022Evening ShiftPhysicsWave OpticsActual
In a double slit experiment with monochromatic light, fringes are obtained on a screen placed at some distance from the plane of slits. If the screen is moved by 5 × 10 - 2 m towards the slits, the change in fringe width is 3 × 10 - 3 cm . If the distance between the slits is 1 mm , then the wavelength of the light will be____ nm .
Correct answer
0
Step-by-step solution
We know that the fringe width in YDSE is β = λ D d ⇒ Δ β = λ d Δ D ⇒ λ = Δ β d Δ D = 3 × 10 - 3 × 10 - 2 × 10 - 3 5 × 10 - 2 = 6 × 10 - 7   m = 600   nm