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JEE Main 202118 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
18 March
Shift
Morning Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2021 · 18 March · Morning Shift · Physics · Wave Optics

In Young's double slit arrangement, slits are separated by a gap of...

In Young's double slit arrangement, slits are separated by a gap of 0.5mm0 . 5mm, and the screen is placed at a distance of 0.5m0 . 5m from them. The distance between the first and the third bright fringe formed when the slits are illuminated by a monochromatic light of 5890Ao5890\overset{o}{A} is :-

Options

  1. A1178×10–9m1178 \times {10}^{– 9}m
  2. B1178×10–6m1178 \times {10}^{– 6}m
  3. C1178×10–12m1178 \times {10}^{– 12}m
  4. D5890×10–7m5890 \times {10}^{– 7}m

Correct answer

B. 1178×10–6m1178 \times {10}^{– 6}m

Step-by-step solution

β=\lambdaDd=5890×10−10×0.50.5×10−3\beta = \dfrac{\lambdaD}{d} = \dfrac{5890 \times {10}^{- 10} \times 0 . 5}{0 . 5 \times {10}^{- 3}}
=589×10−6m= 589 \times {10}^{- 6}m
Distance between first and third bright fringe is 2β=2×589×10−6m2\beta = 2 \times 589 \times {10}^{- 6}m
=1178×10−6m= 1178 \times {10}^{- 6}m
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