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JEE Main 202126 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Morning Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2021 · 26 February · Morning Shift · Physics · Wave Optics

In a Young's double slit experiment two slits are separated by 2mm...

In a Young's double slit experiment two slits are separated by 2mm2mm and the screen is placed one meter away. When a light of wavelength 500nm500nm is used, the fringe separation will be :

Options

  1. A1mm1mm
  2. B0.50mm0 . 50mm
  3. C0.75mm0 . 75mm
  4. D0.25mm0 . 25mm

Correct answer

D. 0.25mm0 . 25mm

Step-by-step solution

β=\lambdaDd=500×10−9×12×10−3\beta = \dfrac{\lambdaD}{d} = \dfrac{500 \times {10}^{- 9} \times 1}{2 \times {10}^{- 3}}

β=52×10−4m=2.5×10−1mm\beta = \dfrac{5}{2} \times {10}^{- 4}m = 2 . 5 \times {10}^{- 1}mm

b=0.25mmb = 0 . 25mm

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