JEE Main202126 Feb 2021Morning ShiftPhysicsWave OpticsActual
In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be :
Options
- A1   mm
- B0 . 50   mm
- C0 . 75   mm
- D0 . 25   mm
Correct answer
D. 0 . 25   mm
Step-by-step solution
β = λ D d = 500 × 10 - 9 × 1 2 × 10 - 3 β = 5 2 × 10 - 4   m = 2 . 5 × 10 - 1   mm b = 0 . 25   mm