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JEE Main202124 Feb 2021Morning ShiftPhysicsWave OpticsActual

In a Young's double slit experiment, the width of the one of the slit is three times the other slit. The amplitude of the light coming from a slit is proportional to the slit-width. Find the ratio of the maximum to the minimum intensity in the interference pattern.

Options

  1. A1 : 4
  2. B2 : 1
  3. C3 : 1
  4. D4 : 1

Correct answer

D. 4 : 1

Step-by-step solution

⇒ A 2 = 3   A 1 I max I min = I 1 + I 2 I 1 - I 2 2 ∵ Intensity I ∝ A 2 ⇒ I max I min = A 1 + A 2 A 1 − A 2 2 = A 1 + 3 A 1 A 1 − 3 A 1 2 = 4 A 1 2 A 1 2 = 4 : 1

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