Two coherent sources of sound, S 1 and S 2 , produce sound waves of the same wavelength λ = 1 m are in phase. S 1 and S 2 are placed 1 . 5 m apart (see fig). A listener, located at L , directly in front of S 2 , finds that the intensity is at a minimum when he is 2 m away from S 2 . The listener moves away from S 1 , keeping the distance from S 2 fixed. The adjacent maximum of intensity is observed when the list

Step-by-step solution

Given, Two sources od same wavelength, λ = 1   m Distance between two sources, S 1 S 2 = 1 . 5   m Distance of listener from the source S 2 , S 2 L = 2   m Condition for minimum intensity, at 2   m is Path difference, P . D . = ( 2 n + 1 ) λ 2     . . . ( 1 ) ⇒ P . D . = 2 2 + ( 1 . 5 ) 2 = ( 2 n + 1 ) λ 2 ⇒ 2 . 5 = ( 2 n + 1 ) λ 2     . . . ( 1 ) Now, the path difference between the rays is so that the adjacent maxima is obtained, P . D . = d