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JEE Main 201912 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
12 April
Shift
Evening Shift
Subject
Physics
Chapter
Wave Optics

JEE Main 2019 · 12 April · Evening Shift · Physics · Wave Optics

A system of three polarizers P _ 1 , P _ 2 , P _ 3 is set up such...

A system of three polarizers P1,P2,P3{P}_{1}, {P}_{2}, {P}_{3} is set up such that the pass axis of P3{P}_{3} is crossed with respect to that of P1{P}_{1} . The pass axis of P2{P}_{2} is inclined at 60o{60}^{o} to the pass axis of P3.{P}_{3} . When a beam of unpolarized light of intensity Io{I}_{o} is incident on P1,{P}_{1}, the intensity of light transmitted by the three polarizers is II . The ratio (Io/I)\left({I}_{o} / I\right) equals (nearly):A system of three polarizers P _ 1 , P _ 2 , P _ 3 is set up such that the pass axis of P _ 3 is crossed with respect

Options

  1. A5.335.33
  2. B16.0016.00
  3. C1.801.80
  4. D10.6710.67

Correct answer

D. 10.6710.67

Step-by-step solution

A system of three polarizers P _ 1 , P _ 2 , P _ 3 is set up such that the pass axis of P _ 3 is crossed with respect
The intensity of light coming out of 1st Polaroid will be I1=I02{I}_{1} = \dfrac{{I}_{0}}{2}
From Malus law I=I0cos⁡2θI = {I}_{0}\cos^{2} \theta
From Polaroid 2: I=I02cos⁡230°=I02(32)2=3I08I = \dfrac{{I}_{0}}{2}\cos^{2} 30 ° = \dfrac{{I}_{0}}{2}{\left(\dfrac{\sqrt{3}}{2}\right)}^{2} = \dfrac{3{I}_{0}}{8}
From Polaroid 3: I=3I08cos⁡260°=3I08(12)2=3I032I = \dfrac{3{I}_{0}}{8}\cos^{2} 60 ° = \dfrac{3{I}_{0}}{8}{\left(\dfrac{1}{2}\right)}^{2} = \dfrac{3{I}_{0}}{32}
Now, I0I=323=10.67\dfrac{{I}_{0}}{I} = \dfrac{32}{3} = 10.67
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