JEE Main201911 Jan 2019Morning ShiftPhysicsWave OpticsActual
In a Young's double slit experiment, the path difference, at a certain point on the screen, betwen two interfering waves is 1 8 th of wavelength. The ratio of the intensity at this point to that at the centre of a bright fringe is close to:
Options
- A0.74
- B0.85
- C0.94
- D0.8
Correct answer
B. 0.85
Step-by-step solution
Given, path difference, x= 8 Phase difference ( ) is given by = 2 ( x ) = (2 ) 8 = 4 For two sources in different phases, array l I=I₀ ² ( 8 ) 1 I₀ = ² ( 8 ) = 1+ 4 2 = 1+ 1 2 2 =0.85 array