In a Young's double slit experiment, the path difference, at a certain point on the screen, betwen two interfering waves is (1)/(8) th of wavelength. The ratio of the intensity at this point to that at the centre of a

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Correct answer: B. 0.85

Given, path difference, Δ x=(λ)/(8) Phase difference (Δ φ) is given by Δ φ=(2 π)/(λ)(Δ x)Δ φ=((2 π))/(λ) (λ)/(8)=(π)/(4) For two sources in different phases, array l I=I_ 0 ^ 2 ((π)/(8)) 1 I_ 0 = ^ 2 ((π)/(8)) =(1+ (π)/(4))/(2)= 1+ 1 2 2 =0.85 array

In a Young's double slit experiment, the path difference, at a...

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