JEE Main 20199 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 9 January
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Wave Optics
JEE Main 2019 · 9 January · Morning Shift · Physics · Wave Optics
Two coherent sources produce waves of different intensities which...
Two coherent sources produce waves of different intensities which interfere. After interference, the ratio of the maximum intensity to the minimum intensity is The intensity of the waves are in the ratio:
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
{I}_\max = {\left(\sqrt{{I}_{1}} + \sqrt{{I}_{2}}\right)}^{2}
{I}_\min = {\left(\sqrt{{I}_{1}} - \sqrt{{I}_{2}}\right)}^{2}
⇒ \dfrac{{I}_\max}{{I}_\min} = \dfrac{{( \sqrt{{I}_{1}} + \sqrt{{I}_{2}} )}^{2}}{{( \sqrt{{I}_{1}} - \sqrt{{I}_{2}} )}^{2}}
{I}_\min = {\left(\sqrt{{I}_{1}} - \sqrt{{I}_{2}}\right)}^{2}
⇒ \dfrac{{I}_\max}{{I}_\min} = \dfrac{{( \sqrt{{I}_{1}} + \sqrt{{I}_{2}} )}^{2}}{{( \sqrt{{I}_{1}} - \sqrt{{I}_{2}} )}^{2}}